Mohon tunggu...
Asep Setiawan
Asep Setiawan Mohon Tunggu... Membahasakan fantasi. Menulis untuk membentuk revolusi. Dedicated to the rebels.

Nalar, Nurani, Nyali. Curious, Critical, Rebellious. Mindset, Mindmap, Mindful

Selanjutnya

Tutup

Inovasi

Leadership Parameters and Bifurcation of Political Unrest: a Mathematical Formalism with Cases Study

16 September 2025   14:54 Diperbarui: 16 September 2025   14:54 82
+
Laporkan Konten
Laporkan Akun
Kompasiana adalah platform blog. Konten ini menjadi tanggung jawab bloger dan tidak mewakili pandangan redaksi Kompas.
Lihat foto
Bagikan ide kreativitasmu dalam bentuk konten di Kompasiana | Sumber gambar: Freepik

Substitute into (9a) to get a single scalar equation in EE^*E (and parameters \Theta):

A2(E)(A1(E)2A2(E))2+A1(E)(A1(E)2A2(E))+A0(E)=0.A_2(E^*)\left(-\frac{A_1(E^*)}{2A_2(E^*)}\right)^2 + A_1(E^*)\left(-\frac{A_1(E^*)}{2A_2(E^*)}\right) + A_0(E^*) = 0.A2(E)(2A2(E)A1(E))2+A1(E)(2A2(E)A1(E))+A0(E)=0.

This simplifies to the discriminant condition:

(E)=A1(E)24A2(E)A0(E)=0.(10)\boxed{ \; \Delta(E^*) \;=\; A_1(E^*)^2 \;-\; 4 A_2(E^*) A_0(E^*) \;=\; 0. \; } \tag{10}(E)=A1(E)24A2(E)A0(E)=0.(10)

Thus the fold locus is given by all EE^*E solving (10). For each such EE^*E we can compute PP^*P via (9b) and TT^*T via (5), and then find E\mu_EE from (6). The resulting E\mu_EE is the candidate crit()\mu_{\mathrm{crit}}(\Theta)crit() where the fold occurs.

Remark: Because AiA_iAi depend on SE(E)S_E(E^*)SE(E), K(E)K(E^*)K(E), etc., (10) is generally a nonlinear equation in EE^*E that must be solved numerically or symbolically (if closed forms are available). But it is explicit and amenable to algebraic manipulation (e.g., resultant elimination) if required.

5. Jacobian at equilibrium --- explicit partial derivatives

To analyze local stability and bifurcation nondegeneracy, compute the Jacobian matrix J=F/XJ=\partial F/\partial XJ=F/X evaluated at the equilibrium X=(T,E,P)X^*=(T^*,E^*,P^*)X=(T,E,P).

From (1)--(3) the Jacobian entries Jij=Xi/XjJ_{ij}=\partial \dot X_i/\partial X_jJij=Xi/Xj are:

J=(TTETPTTEEEPETPEPPP)(T,E,P).J = \begin{pmatrix} \partial_T \dot T & \partial_E \dot T & \partial_P \dot T\\[4pt] \partial_T \dot E & \partial_E \dot E & \partial_P \dot E\\[4pt] \partial_T \dot P & \partial_E \dot P & \partial_P \dot P \end{pmatrix}_{(T^*,E^*,P^*)}.J=TTTETPETEEEPPTPEPP(T,E,P).

Compute each entry:

Mohon tunggu...

Lihat Konten Inovasi Selengkapnya
Lihat Inovasi Selengkapnya
Beri Komentar
Berkomentarlah secara bijaksana dan bertanggung jawab. Komentar sepenuhnya menjadi tanggung jawab komentator seperti diatur dalam UU ITE

Belum ada komentar. Jadilah yang pertama untuk memberikan komentar!
LAPORKAN KONTEN
Alasan
Laporkan Konten
Laporkan Akun